Logic Problem Solution:
According to the introduction, each of the 24 faces of the Letter
Cubes has a different letter on it. Given the word MOCK, we
arbitrarily assign M to cube 1, O to cube 2, C to cube 3, and K
to cube 4. From the word CONE, E cannot be on cube 2 or 3; and
from the word MARE, E cannot be on cube 1 with M. E is on a face
of cube 4. Then from CONE, N is on cube 1 with M. T isn't on
cube 4 with E (STEW), nor on cube 1 or 2 (TONY); T is on cube 3.
Then Y is on cube 4 (TONY). From MARE, A and R are on cubes 2
and 3 or vice versa. Then W must be on cube 1 or cube 4 (WARD).
W isn't on 4 (STEW) and must be on 1. S is on 2 (STEW) and D on
4 (MARE, WARD). From VICE, V and I must be on cubes 1 and 2 or vice
versa. However, from DISH, I cannot be on cube 2 with S. So,
I in VICE is on cube 1 and V on 2; and H in DISH is on cube 3.
From CLOG, L and G are on cubes 1 and 4 or vice versa. From CLIP,
L can't be on cube 1 with I; L is on 4 and G in CLOG on 1. P is
on cube 2 (CLIP). By QUIP, U isn't on cube 1 with I or cube 2
with P. From FURL, then, U isn't on cube 4 and must be on cube
3--with A; R (MARE) is on cube 2. Then F is the sixth letter on
cube 1 (FURL), and Q is the sixth letter on cube 4 (QUIP). From FAZE,
Z is the sixth letter on cube 2. By elimination, B is on cube
3. In sum, the faces on the four cubes are
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