Logic Problem Solution: The Krispy Kreme Prom From the introduction, no two of the top five Krispy Kreme doughnut salespeople brought in the same amount. By clue 1, the five prize winners sold a total of $4,000 worth of doughnuts, with the 5th highest salesperson having sold $400 worth. Three of the top five are mentioned in clue 3: Long, who sold $200 more than Candace, who sold $400 more than the one who won Mr. Russo's hand-made silver ring. By clue 5, Elise sold twice as much as Young. Elise isn't Long (10), so either Elise got the ring as a prize or Elise is the fourth top salesperson to the three listed in clue 3. If Elise had won the silver ring and we let Young be the one who sold the least amount, $400 worth of Krispy Kremes (1), Elise would have sold $800 worth to win the ring, Candace's sales total would have been $1,200, and Long would have sold $1,400 worth of doughnuts--a total of $3,800, leaving the fifth winner with $200 in sales and contradicting clue 1. If we let Young having sold more than the $400, the fifth person would have sold even less. So, Elise didn't choose the ring; she is the fourth prize winner to the three in clue 3. In clue 5, then, either Young is Candace, Young received the ring as a prize, or Young is the fifth top salesperson to the four already recovered. If Young were Candace and we let the person who won Mr. Russo's ring be the $400 salesperson, by clues 3 and 5, Candace Young would have brought in $800, Long $1,000, and Elise $1,600--a total of $3,800, leaving the fifth person with $200 in sales and contradicting clue 1. If the ring winner had sold more than the $400, of course, the fifth person would have brought in even less than $200. Therefore, Young isn't Candace. If Young had chosen the silver ring as a prize, either Young would have sold $400 worth of doughnuts or Young would have been the 4th highest salesperson. If Young had gotten the ring and had sold $400 worth, both Candace (3) and Elise (5) would have had sales of $800--by the intro, no. If Young had been the 4th highest salesperson, then the four highest would have sold $3,600 worth of doughnuts total (1). Letting Young's sales equal X, by clues 3 and 5, Candace's would have been X + 400, Long's X + 600, and Elise's 2X, so that 5X + 1,000 would equal $3,600, or X would equal $520. So Young would have sold $520 worth of Krispy Kremes, Candace $920, Long $1,120, and Elise $1,040. By clue 2, the person who attended the Blades ice hockey game with Mrs. Bennett sold twice as much as junior Dietz. There is no way for this clue to work given the arrangement with Young as 4th highest and ring winner. So, Young is the fifth prize winner to Long, Candace, the one who won the silver ring, and Elise. Either Young or the ring winner sold $400 worth of doughnuts (1, 3, 5). If Young had, then Elise would have sold $800 worth (5), leaving $2,800 in sales for the three in clue 3. Letting the ring winner's total sales be X, Candace's would be X + 400 and Long's X + 600--or 3X + 1,000 equals 2,800 and X = 600. So, the ring winner would have sold $600 worth, Candace $1,000, and Long $1,200. The only way clue 2 could fit into this arrangement would be if Dietz had won the ring and Long the Blades game with Mrs. Bennett--no (6). Therefore, the ring winner sold $400 worth of Krispy Kremes, Candace sold $800, and Long brought in $1,000, a total of $2,200 and leaving $1,800 between Elise and Young (1). By clue 5, Elise was top salesperson with $1,200 and Young fourth with $600. By clue 2, Dietz is the junior who won the silver ring made by Mr. Russo, and Candace picked going to the Blades hockey game with Mrs. Bennett. By clue 9, Jeffrey is Long. Adam is Young and Kerrie Dietz (8). Neither Elise (4) nor Adam (8) went to see Hamlet with Mrs. Furman, so Jeffrey did. By clue 10, Elise picked up the five +10% Calculus I test boosts, so Adam won the dinner for four cooked by Mr. Scanlon. Elise is Walls and Candace Gore (7). The top five Krispy Kreme doughnuts salespeople, the amounts they sold, and the prizes they won are
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